
思路:模拟
class Solution {
public:
string licenseKeyFormatting(string s, int k) {
string ans;
int cnt=0;
for(int i=s.size()-1;i>=0;--i){
if(s[i]!='-'){
cnt++;
ans.push_back(toupper(s[i]));
if(cnt%k==0)
ans.push_back('-');
}
}
if(ans.size()&&ans.back()=='-')
ans.pop_back();
reverse(ans.begin(),ans.end());
return ans;
}
};