根据操作系统的差异拼接文件路径

以文件和文件的相对路径所包括的各个目录为顺序给定一个列表，根据操作系统差异拼接为文件路径字符串并输出。

请在以下选项中选出正确答案

import os

def print_dir_name(dir_names):
    print(os.sep.join(dir_names))

if __name__ == "__main__":
    print_dir_name(['china', 'guangdong', 'shenzhen.txt'])

import os

def print_dir_name(dir_names):
    print(os.newline.join(dir_names))

if __name__ == "__main__":
    print_dir_name(['china', 'guangdong', 'shenzhen.txt'])

import os

def print_dir_name(dir_names):
    print(os.directory_separator.join(dir_names))

if __name__ == "__main__":
    print_dir_name(['china', 'guangdong', 'shenzhen.txt'])

import os

def print_dir_name(dir_names):
    print(os.separator.join(dir_names))

if __name__ == "__main__":
    print_dir_name(['china', 'guangdong', 'shenzhen.txt'])

正确答案：A