与门，或门，与非门，异或门的python实现

import numpy as np
x = np.array([0,1])

def date():
    w = np.array([1,0])
    b = 0.1
    x = [1,1]
    # s = np.matmul(w,x)+b
    s = np.sum(w * x) + b
    print(int(round(s,0)))

def get_and(x1, x2):
    x = np.array([x1, x2])
    y = np.array([0.5, 0.5])  # 权重
    b = -0.7  # 偏置
    tmp = np.sum(x * y) + b
    if tmp <= 0:
        return 0
    else:
        return 1


def get_nand(x1, x2):#与非门
    x = np.array([x1, x2])
    y = np.array([-0.5, -0.5])
    b = 0.7
    tmp = np.sum(x * y) + b
    if tmp <= 0:
        return 0
    else:
        return 1


def get_or(x1, x2):
    x = np.array([x1, x2])
    y = np.array([0.5, 0.5])
    b = -0.2
    tmp = np.sum(x * y) + b
    if tmp <= 0:
        return 0
    else:
        return 1


def get_xor(x1, x2):
    s1 = get_nand(x1, x2)
    s2 = get_or(x1, x2)
    y = get_and(s1, s2)
    return y

if __name__ == "__main__":
    print(get_xor(0, 1))  # 1
    print(get_xor(1, 0))  # 1
    print(get_xor(0, 0))  # 0
    print(get_xor(1, 1))  # 0

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